0=6t^2-24t+18

Solution for 0=6t^2-24t+18 equation:

0=6t^2-24t+18

We move all terms to the left:

0-(6t^2-24t+18)=0

We add all the numbers together, and all the variables

-(6t^2-24t+18)=0

We get rid of parentheses

-6t^2+24t-18=0

a = -6; b = 24; c = -18;
Δ = b2-4ac
Δ = 242-4·(-6)·(-18)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-12}{2*-6}=\frac{-36}{-12}
=+3
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+12}{2*-6}=\frac{-12}{-12}
=1
$